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Question

A line is drawn through a fixed point P(a,b) to cut the circle x2+y2=r2 at A and B. Then PA.PB is equal to

A
(a+b)2r2
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B
a2+b2r2
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C
(ab)2+r2
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D
none of these
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Solution

The correct option is B a2+b2r2
Given point P(a,b) and AB is chord which passes through point P
M is the midpoint of AB and
BM=AM(1)
in POM
(OM)2=(OP)2(PM)2(OM)2=(a2+b2)(PM)2(2)
In AOM
(OM)2=(OA)2(AM)2(OM)2=r2(AM)2(3)
From (2) and (3)
(a2+b2)(PM)2=r2(AM)2(a2+b2)r2=(PM)2(AM)2(a2+b2r2)=(PMAM)(PM+AM)
From (1)
(a2+b2r2)=PA(PM+BM)(a2+b2r2)=PAPB

892371_599296_ans_5fd391889577475599fbefa54d052fe4.png

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