A line is drawn through the point (1,2) to meet the coordinate axes at P and Q such that it forms a triangle triangle OPQ, where O is the origin. If the area of the triangle OPQ is least, the the slope of the line PQ is
A
−1/4
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B
−4
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C
−2
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D
−1/2
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Solution
The correct option is C−2 Equation of line passing through (1,2) with slope m is y−2=m(x−1) Area of ΔOPQ=(m−2)22|m| Δ=m2−4m+42m Δ is least if 2m=m2 ⇒m2=4 ∴m=2 or −2.