The correct option is B y=−2x+1
We need to find the line which is parallel to 2x+y=3 and passes through the point (0,1).
We first need to write 2x+y=3 in standard form.
2x+y=3
y=−2x+3
The above line has slope '-2' and y-intercept as '3'.
Any line parallel to the above line has the slope as '-2'.
So, the slope of the required line is '-2' and also it passes through (0,1) this means that its y-intercept is '1'.
Slope intercept form of a line: y=mx+c where 'm' is the slope and 'c' is the y-intercept of the line.
The equation of the required line would be:
y=−2x+1