A line L passes through the point P(5, -6, 7) and is parallel to the planes x + y + z = 1 and 2x - y - 2z = 3.Find the direction ratios of the line of intersection of the given planes.
A
<11,−4,−9>
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B
<−1,−4,3>
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C
<1,−4,3>
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D
<1,−4,−3>
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Solution
The correct option is A<11,−4,−9> A line L passes through the point P(5,−6,7) and is parallel to the planes
x+y+z=1 ......(1)
2x−y−2z=3......(2)
the direction ratios of the line of intersection of the given planes =
⇒x+y+z=1,2x−y−2z=3
(x+y+z−1)+k(2x−y−2z−3)=0 ......(3)
it passes through (5,−6,7) substitute the value in eqn (3)
(5−6+7−1)+k(10+6−14−3)=0
5+k(−1)=0
5−k=0
k=5 ......(4)
substitute eqn (4) in (3) we will get:
(x+y+z−1)+5(2x−y−2z−3)=0
⇒x+y+z−1+10x−5y−10z−15=0
⇒11x−4y−9z−16=0
⇒11x−4y−9z=16
which is the equation of a plane, hence the direction ratios of the line
of intersection of the given planes is equal to <11,−4,−9>