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Question

A line L passes through the points (1, 1) and (2, 0) and another line L’ passes through [12,0] and perpendicular to L. Then the area of the triangle formed by the lines L, L’ and y –axis, is

A
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B
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C
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D
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Solution

The correct option is D
Here Lx+y=2 and L2x2y=1
Equation of y-axis is x = 0
Hence the vertices of the triangle are A(0,2),B(0,12) and C(54,34). Therefore, the area of the triangle is 12∣ ∣ ∣021012154341∣ ∣ ∣=2516

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