A line L passes through the points (1, 1) and (2, 0) and another line L’ passes through [12,0] and perpendicular to L. Then the area of the triangle formed by the lines L, L’ and y–axis, is
A
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B
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C
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D
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Solution
The correct option is D Here L≡x+y=2andL′≡2x−2y=1 Equation of y-axis is x = 0 Hence the vertices of the triangle are A(0,2),B(0,12)andC(54,34). Therefore, the area of the triangle is 12∣∣
∣
∣∣0210−12154341∣∣
∣
∣∣=2516