A line m through A is drawn parallel to BD. A point S moves such that its distances from BD and the vertex A are equal. If the locus of S cuts the line m at T2 and T3, and AC at T1 then ar(△T1T2T3) in square units is
A
12
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B
23
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C
1
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D
2
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Solution
The correct option is C 1 Since AG=√2 ∴AT1=T1G=1√2 As A is the focus T1 is the vertex and BD is the directrix of parabola Also T2T3 is latusrectum ∴T2T3=4.1√2 Therefore area T1T2T3=12×1√2×4√2=1