A line of force originates from a charge q1 at an angle - and terminates at a charge -q2 at an angle - The value of beta in terms of - is-

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Properties of Field Lines

A line of for...

Question

A line of force originates from a charge $q_{1}$ at an angle $α$ and terminates at a charge $- q_{2}$ at an angle $β$ . The value of $b e t a$ in terms of $α$ is:

2 s i n^{- 1} (\sqrt{\frac{q_{1}}{q_{2}}} s i n (\frac{α}{2}))

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2 c o s^{- 1} (\sqrt{\frac{q_{1}}{q_{2}}} s i n (\frac{α}{2}))

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2 t a n^{- 1} (\sqrt{\frac{q_{1}}{q_{2}}} s i n (\frac{α}{2}))

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2 s i n^{- 1} (\frac{q_{1}}{q_{2}} s i n (\frac{α}{2}))

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Solution

The correct option is A $2 s i n^{- 1} (\sqrt{\frac{q_{1}}{q_{2}}} s i n (\frac{α}{2}))$

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A line of force originates from a charge q1 at an angle α and terminates at a charge −q2 at an angle β. The value of beta in terms of α is:

The correct option is A 2sin−1(√q1q2sin(α2))

A line of force originates from a charge $q_{1}$ at an angle $α$ and terminates at a charge $- q_{2}$ at an angle $β$ . The value of $b e t a$ in terms of $α$ is:

The correct option is A $2 s i n^{- 1} (\sqrt{\frac{q_{1}}{q_{2}}} s i n (\frac{α}{2}))$