A line parallel to BC in △ ABC meets AB and AC in D and E respectively. If AD = (4x - 3)cm, DB = (3x - 1) cm, AE = (8x - 7)cm, EC = (5x -3)cm, the admissible value of x is
A
1
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B
0
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C
2
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D
3
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Solution
The correct option is A1 DE∥BC Thus, ADDB=ACEC ⇒4x−33x−6=8x−75x−3 ⇒20x2−27x+9=24x2−29x+7 ⇒4x2−2x−2=0 ⇒2x2−x−1=0 ⇒(2x+1)(x−1)=0 Thus, x=1