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Question

A line passes through the point P (1, 2) such that its intercept between the axes is bisected at P. The equation of the line is
(a) x + 2y = 5
(b) xy + 1 = 0
(C) x + y – 3 = 0
(d) 2x + 2y – 4 = 0


Solution

Suppose equation of the line is given by xa+yb=1

Since intercept between is axis is bisected 


a+02=1 and 0+b2=2 By mid point formulai.e. a=2 and b=4 equation of line is x2+y4=1i.e. 2x+y=4i.e. 2x+y-4=0

Hence, the correct answer is option D.

Mathematics
RD Sharma XI (2019)
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