A line passes through the points $(4, 3)$ and $(- 4, - 9)$ , what is the $y$ -intercept of the line.

(0, 2)

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(2, 0)

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(0, - 3)

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(- 3, 0)

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Solution

The correct option is C $(0, - 3)$
Slope, $m =$ $\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$
$m = \frac{- 9 - 3}{- 4 - 4}$
$m = \frac{3}{2}$
To find the $y$ -intercept, $y = m x + b$
$3 = \frac{3}{2} (4) + b$
$b = - 3 = y$ - intercept
Therefore, $y$ -intercept of the line is $(0, - 3)$ .

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A line passes through the points (4,3) and (−4,−9), what is the y-intercept of the line.

The correct option is C (0,−3)Slope, m= y2−y1x2−x1m=−9−3−4−4m=32To find the y-intercept, y=mx+b3=32(4)+bb=−3=y- interceptTherefore, y-intercept of the line is (0,−3).

A line passes through the points $(4, 3)$ and $(- 4, - 9)$ , what is the $y$ -intercept of the line.

The correct option is C $(0, - 3)$
Slope, $m =$ $\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$
$m = \frac{- 9 - 3}{- 4 - 4}$
$m = \frac{3}{2}$
To find the $y$ -intercept, $y = m x + b$
$3 = \frac{3}{2} (4) + b$
$b = - 3 = y$ - intercept
Therefore, $y$ -intercept of the line is $(0, - 3)$ .