A line passes through the points whose position vectors are i-j-2k- and i-3j-k- The position vector of a point on it at a unit distance from the first point is

The correct option is D None of theseThe direction vector of the line is 4ĵ 3k̂ and so the unit vector in this direction becomes 4ĵ 3k̂5 Now the ...

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Collinear Vectors

A line passes...

Question

A line passes through the points whose position vectors are $\to i + \to j - 2 \to k$ and $\to i - 3 \to j + \to k$ . The position vector of a point on it at a unit distance from the first point is

\frac{1}{5} (6 \to i + \to j - 7 \to k)

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\frac{1}{5} (4 \to i + 9 \to j - 13 \to k)

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\to i - 4 \to j + 3 \to k

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None of these

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Similar questions

4 \to i - 3 \to j + \to k, 2 \to i - 4 \to j + 5 \to k, \to i - \to j

\to i + \to j + 2 \to k

\to i + 2 \to j + \to k

\to i + \to j + \to k

A unit vector coplanar with $\to i + \to j + 3 \to k and \to i + 3 \to j + \to k$ and perpendicular to $\to i + \to j + \to k$ is

6

\to i - 2 \to j + 2 \to k

\to i - \to j

\to j - \to k

_{1}

\to p = \to i + 2 \to j + 3 \to k

\to a = \to i + 2 \to j + 3 \to k

L

_{2}

\to q = 2 \to i + 3 \to j + \to k

\to b = 3 \to i + \to j + 2 \to k

\to p

L

_{2}

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