A linear equation in two variables can be written in the form $a x + b y + c = 0$ . Now look at the linear equations in Column-I and match them with their constant term $c$ written in the Column-II.
Column-I Column -II
(a) $5 x + 7 y = - 27$ (p) $- 17$
(b) $2 x + y = 17$ (q) $17$
(c) $3 y - 5 x + 17 = 0$ (r) $- 27$
(d) $4 x - 3 y - 27 = 0$ (s) $27$

(a)⇢ r; (b)⇢ p; (c)⇢ q; (d)⇢ s

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(a)⇢ s; (b)⇢ p; (c)⇢ q; (d)⇢ r

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(a)⇢ s; (b)⇢ q; (c)⇢ p; (d)⇢ r

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(a)⇢ r; (b)⇢ q; (c)⇢ p; (d)⇢ s

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Solution

The correct option is B
(a)⇢ s; (b)⇢ p; (c)⇢ q; (d)⇢ r

:An equation of the form $a x + b y + c = 0$ where $a$ , $b$ , $c$ are real numbers $(a, b \neq 0)$ and $x$ , $y$ are variables, is called a linear equation in two variables.
Here ' $a$ ' is called the coefficient of $x$ , $b$ ' is called the coefficient of $y$ and $c$ ' is called constant term.
Explanation for (a)
Rewritten the given equation the form $a x + b y + c = 0$
(a) $5 x + 7 y = - 27$
$\Rightarrow 5 x + 7 y + 27 = 0$
Equating the above equation to the general form, we get $c = 27$ .
⇒(a)⇢ s
Therefore, (a) matches to (s)
Explanation for (b)
(b) $2 x + y = 17$
$\Rightarrow 2 x + y - 17 = 0$
Equating the above equation to the general form, we get $c = - 17$ .
⇒(b)⇢ p
Therefore, (b) matches to (p)
Explanation for (c)
(c) $3 y - 5 x + 17 = 0$
Equating the above equation to the general form, we get $c = 17$ .
⇒(c)⇢ q
Therefore, (c) matches to (q)
Explanation for (d)
(d) $4 x - 3 y - 27 = 0$
Equating the above equation to the general form, we get $c = 27$ .
⇒(d)⇢ s
Therefore, (d) matches to (s)
By that, we conclude, (a)⇢ s; (b)⇢ p; (c)⇢ q; (d)⇢ r.
Correct Answer is option B

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Match the two columns:

Column I	COLUMN II
(A) $4 x + 3 y = 12$ cuts $x$ and $y$ axes	(p) $4 x - 3 y = 7$
(B) $4 - 3 x = 0$ can be written as	(q) at $(3, 0)$ and $(0, 4)$
(C) $(3, 4)$ lies on $3 y = a x + 7$ , then $a$ =	(r) $- 3 x + 0 y + 4 = 0$
(D) $(1, - 1)$ is a solution of the equation	(s) $\frac{5}{3}$

Choose the correct option

-

2 x + 3 y = 9.3 ¯ 5

x - \frac{y}{5} - 10 = 0

(i) 2 x + 3 y = 9.35 (i i) - 2 x + 3 y = 6 (i i i) x = 3 y

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