A linear harmonic oscillator of force constant 2×106Nm−1 and amplitude 0.01 m has a total mechanical energy of 160 J. Its
A
maximum potential energy is 100 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
maximum kinetic energy is 100 J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
maximum potential energy is 160 J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
minimum potential energy is zero
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct options are B maximum kinetic energy is 100 J C maximum potential energy is 160 J Maximum kinetic energy =12kA2=12×(2×106)×10−4=100J Maximum potential energy = Total mechanical energy =160J