Question

A linear simple harmonic oscillation has a total energy of $250\text{J}$. If the potential energy at mean position is $50\text{J}$, then find the maximum kinetic energy.

• A. $50\text{J}$
• B. $200\text{J}$
• C. $100\text{J}$
• D. $150\text{J}$

Answer 1

The correct option is B $200\text{J}$

Given, Total mechanical energy $\left(E\right)=250\text{J}$
Potential energy at mean position $\left(U\right)=50\text{J}$
At mean position, potential energy is minimum.
$\therefore \text{KE}$ is maximum.
${\text{KE}}_{max}=E-U_{min}=250-50=200\text{J}$