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Standard XII

Physics

Bernoulli's Principle

A liquid ente...

Question

A liquid enters a tube of variable cross section with a velocity $3 {ms}^{- 1}$ through the wider end and leaves from the narrow and whose radius is half of the wider one. The velocity with which it leaves the tube is:

1.2 {ms}^{- 1}

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12 {ms}^{- 1}

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10 {ms}^{- 1}

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20 {ms}^{- 1}

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Solution

The correct option is B $12 {ms}^{- 1}$
The equation of continuity,

$A_{1} v_{1} = A_{2} v_{2}$

$π (2 r)^{2} v_{1} = π r^{2} v_{2}$

$4 π r^{2} v_{1} = π r^{2} v_{2}$

$v_{2} = 4 \times 3 m / s$

$v_{2} = 12 m / s$

The correct option is B.

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A liquid enters a tube of variable cross section with a velocity 3ms−1 through the wider end and leaves from the narrow and whose radius is half of the wider one. The velocity with which it leaves the tube is:

The correct option is B 12ms−1The equation of continuity,A1v1=A2v2π(2r)2v1=πr2v24πr2v1=πr2v2v2=4×3m/sv2=12m/sThe correct option is B.

A liquid enters a tube of variable cross section with a velocity $3 {ms}^{- 1}$ through the wider end and leaves from the narrow and whose radius is half of the wider one. The velocity with which it leaves the tube is:

The correct option is B $12 {ms}^{- 1}$
The equation of continuity,

$A_{1} v_{1} = A_{2} v_{2}$

$π (2 r)^{2} v_{1} = π r^{2} v_{2}$

$4 π r^{2} v_{1} = π r^{2} v_{2}$

$v_{2} = 4 \times 3 m / s$

$v_{2} = 12 m / s$

The correct option is B.