Question

A liquid flowing through a horizontal pipeline of varying cross section. At a certain cross section, the diameter of the pipe is 5cm and the velocity of flow of liquid is 25cms-1. Calculate the velocity of flow at another cross section where the diameter of the pipe is 1cm.

Answer 1

Dear Student,

$$\begin{gathered} Bytheequationofcontinuity \\ {A}_1{V}_1=A_2{V}_2 \\ \mathrm{\pi }{r_1}^2{V}_1=\mathrm{\pi }{r_2}^2{V}_2\Rightarrow {r_1}^2{V}_1={r_2}^2{V}_2 \\ {d_1}^2{V}_1={d_2}^2{V}_2\Rightarrow 5^2\times 25=1^2{V}_2 \\ {V}_2=625cm/s \end{gathered}$$
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