Question

A liquid flows through a pipe of 1 mm in diameter and 10 cm length under a pressure of 10 ^ 4 dyne per CM square. calculate the rate of flow and speed of the liquid leaking from the tube . the coefficient of viscosity of fluid is 1.2 centipoise.

Answer 1

$$\begin{gathered} DearStudent, \\ Weknowthat, \\ Q=\frac{△P{\mathrm{\pi r}}^2}{8\eta l} \\ given \\ △P={10}^4\frac{dyne}{c{m}^2}={10}^{3}N/m^2 \\ d=1mm \\ \Rightarrow r=0.5\times {10}^{-3}m \\ \eta =1.2centipoise \\ =1.2\times {10}^{-3}Pa.s \\ Putintheformulae \\ Q=\frac{{10}^3\times 3.14\times {10}^{-6}}{8\times 1.2\times {10}^{-3}\times 10\times 4\times {10}^{-2}} \\ Q=0.8m^3/sec \\ Regards \end{gathered}$$