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Question

A liquid flows through two capillary tubes connected in series. Their lengths are L and 2L and radii r and 2r respectively. Then the pressure differences across the first and the second tube are in the ratio

A
8:1
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B
4:1
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C
2:1
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D
1:8
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Solution

The correct option is A 8:1
given :- l2=2l1&r2=2r1
Since flow rate across 1 = flow rate across 2
[as flow rate remains constant]
π×P1r418gl2=πP2r428gl2
P1P2=l1l2×(r2r1)4=12×24=8


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