Question

A liquid is compressed in a cylinder from a volume of 0.0113$m^3$ at $6.87\times {10}^{6}N/m^2$ pressure to $0.0112m^3$ at $13.73\times {10}^{6}N/m^2$. The compressibility of the liquid is

• A. $1.29\times {10}^{-9}{m}^2/N$
• B. $7.75\times {10}^{8}N/m^2$
• C. $2.4\times {10}^{-9}{m}^2/N$
• D. $8.4\times {10}^{8}N/m^2$

Answer 1

The correct option is A

$1.29\times {10}^{-9}{m}^2/N$

(a)
The compressibility of a liquid is defined as

$\beta =\frac{1}{K}=\frac{-\left(dV/V\right)}{dp}$
$\beta =\frac{-\left(\frac{0.0112-0.0113}{0.0113}\right)}{(13.73\times {10}^6-6.87\times {10}^6)}$
$\beta =1.29\times {10}^{-9}{m}^2/N$