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Question

A liquid is kept in a cylindrical vessel which is rotated about its axis. The liquid rises at the sides. If the radius of the vessel is 0.05 m and the speed of rotation is 2 rev/s. The difference in the height of the liquid at the center of the vessel and its sides will be (π2=10) :

A
3 cm
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B
2 cm
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C
3/2 cm
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D
2/3 cm
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Solution

The correct option is B 2 cmChange in potential energy = change in angular K.ERadius, r=0.05mSpeed of revolution, ω=2rev.s−1⇒mgh=12m(rω)2⇒h=ω2r22g=(0.05)2(2)210=0.02m

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