A liquid is under streamline flow through a horizontal pipe of non uniform cross-sectional area. If the volume rate of flow at a cross-section of area a is V, then volume rate of flow at a different cross-section of area a2 is
A
V2
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B
2V
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C
V4
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D
V
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Solution
The correct option is DV Applying continuity equation at the two cross-sections for the given streamline flow, A×v=constant...(i) Now, for a given time interval Δt, the volume flow rate is, A×v×Δt So, volume flow rate at any cross-section will remain constant.Vi=Vf=V Hence, volume flow rate at second cross-section of area a2=V