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Question

A liquid of density 0.85g/cm3 flows through a calorimeter at the rate of 8.0cm3/s. Heat is added by means of a 250W electric heating coil and a temperature difference of 15C is establised in steady-state conditions between the inflow and the outflow points of the liquid. The specific heat for the liquid will be

A
0.6kcal/kgK
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B
0.3kcal/kgK
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C
0.5kcal/kgK
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D
0.4kcal/kgK
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Solution

The correct option is B 0.6kcal/kgK
In one second, amount of heat supplied = amount of heat absorbed

power P=mass rate×specific heat×temperature difference
specific heat=2500.85×8×15=0.6 cal/gK=0.6 kcal/kgK

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