A liquid of mass $100 g$ loses heat at a rate of $200 J s^{- 1}$ for 1 minute. If the temperature of the liquid drops by $100 ° C$ , calculate the specific capacity of the liquid.

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Solution

Step 1: Information
Given
mass $(m) = 100 g$
Heat supplied $= 200 J s^{- 1}$
Time is one minute
$θ_{R} = 100 ° C$
Find:
The specific heat capacity of the liquid
Step 2: Calculating the specific heat capacity
Heat supply $200 \times 60 = 12000 J$
Heat supplied is given as $m c θ_{R}$
$12000 = 100 \times c \times 100 c = \frac{12000}{100 \times 100} c = 1.2 J g^{- 1} ° C^{- 1}$
Hence the specific heat capacity is $1.2 J g^{- 1} ° C^{- 1}$ .

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A liquid of mass 100g loses heat at a rate of 200Js-1 for 1 minute. If the temperature of the liquid drops by 100°C, calculate the specific capacity of the liquid.

A liquid of mass $100 g$ loses heat at a rate of $200 J s^{- 1}$ for 1 minute. If the temperature of the liquid drops by $100 ° C$ , calculate the specific capacity of the liquid.