Question

A liquid of mass $200g$ exerts a pressure of $0.1Pa$ at the bottom of container. What pressure would it exert if the area of cross section of the container is doubled?

Answer 1

We know that pressure $\left(P\right)=\rho gh=\rho g\left(\frac{V}{A}\right)$

$P\propto \frac{1}{A}$

since, pressure is inversely proportional to the area of cross-section,pressure will be half if the area of cross section of the container is doubled

$\Rightarrow$ Final Pressure $=\frac{0.1}{2}=0.05Pa$