CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A liquid of mass of 100 g at 120 °C is poured into the water at 20 °C. The final temperature recorded is 40 °C. If the specific heat capacity of the liquid is 0.8 Jg-1 °C-1, calculate the initial mass of water.


Open in App
Solution

Given:

The mass of the liquid, M=100g

The temperature of the liquid =120°C

The temperature of water =20°C

The final temperature of the mixture =40°C

The specific heat capacity of the liquid, C=0.8Jg-1°C-1

Finding the initial mass of the water:

The specific heat capacity of water, c=4.182Jg-1°C-1

From the principle of calorimetry, we know that the heat lost by the hot body = the heat gained by the cold body.

so, MC(120-40)=mc(40-20)

100x0.8x80=mx4.182x206400=mx83.64m=76.5

Hence, the mass of the water is 76.5 g.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Specific Heat Capacity
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon