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Standard XII

Physics

Calorimetry

A liquid P if...

Question

A liquid P if specific heat capacity $2400 J k g^{- 1} K^{- 1}$ and at $70^{o} C$ is mixed with another liquid R of specific heat capacity $1000 J k g^{- 1} K^{- 1}$ at $30^{o} C$ . After mixing, the final temperature of the mixture is $40^{o} C$ . Find the ratio of the mass of the liquids mixed?

4 : 5

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8 : 5

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40 : 5

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36 : 5

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Solution

The correct option is D 36 : 5
Let mass of the liquids P and R be $m_{P}$ and $m_{R}$ respectively.

According to calorimeter,
Heat lost by liquid P $=$ Heat gained by liquid R.

$∴ m_{P} C_{P} (70 - 40) = m_{R} C_{R} (40 - 30)$

$m_{P} (2400) (30) = m_{R} (1000) (10)$

$\frac{m_{P}}{m_{R}} = \frac{2400 \times 40}{1000 \times 10} = \frac{48}{5}$

$\frac{m_{P}}{m_{R}} = 48 : 5$

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A liquid P if specific heat capacity 2400Jkg−1K−1 and at 70oC is mixed with another liquid R of specific heat capacity 1000Jkg−1K−1 at 30oC. After mixing, the final temperature of the mixture is 40oC. Find the ratio of the mass of the liquids mixed?

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A liquid P if specific heat capacity $2400 J k g^{- 1} K^{- 1}$ and at $70^{o} C$ is mixed with another liquid R of specific heat capacity $1000 J k g^{- 1} K^{- 1}$ at $30^{o} C$ . After mixing, the final temperature of the mixture is $40^{o} C$ . Find the ratio of the mass of the liquids mixed?