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Question

A liquid P if specific heat capacity 2400Jkg−1K−1 and at 70oC is mixed with another liquid R of specific heat capacity 1000Jkg−1K−1 at 30oC. After mixing, the final temperature of the mixture is 40oC. Find the ratio of the mass of the liquids mixed?

A
4 : 5
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B
8 : 5
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C
40 : 5
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D
36 : 5
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Solution

The correct option is D 36 : 5
Let mass of the liquids P and R be mP and mR respectively.

According to calorimeter,
Heat lost by liquid P = Heat gained by liquid R.

mPCP(7040)=mRCR(4030)

mP(2400)(30)=mR(1000)(10)

mPmR=2400×401000×10=485

mPmR=48:5

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