Question

A liquid stands at the same level in both the limbs of a U-tube when at rest. If area of cross-section of both the
limbs are equal, the difference in heights h of the liquid in the two limbs of U-tube, when the system is given an
acceleration a in horizontal direction as show, is

• A. $\frac{g{L}^2}{aH}$
• B. $\frac{La}{g}$
• C. $\frac{L^{2}a}{Hg}$
• D. $\frac{Hg}{a}$

Answer 1

The correct option is B $\frac{La}{g}$

$P_2+a\rho L=P_1,P_1-P_2=a\rho L,h_1-h_2=\frac{aL}{g}$