A liquid with speed v through a horizontal pipe of cross sectional area A enters into another pipe of double the area of cross-section. The speed of the liquid in the second pipe will be
A
v
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2v
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
v2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
v4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Cv2 Initial area, A1=A
Initial velocity of liquid, v1=v
Let final velocity of liquid, v2
Given final area, A2=2A
By continuity equaiton. A1v1=A2v2 ⇒A×v=(2A)×v2 ⇒v2=v2