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Question

A liquid with speed v through a horizontal pipe of cross sectional area A enters into another pipe of double the area of cross-section. The speed of the liquid in the second pipe will be

A
v
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B
2v
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C
v2
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D
v4
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Solution

The correct option is C v2
Initial area, A1=A
Initial velocity of liquid, v1=v
Let final velocity of liquid, v2
Given final area, A2=2A
By continuity equaiton.
A1v1=A2v2
A×v=(2A)×v2
v2=v2

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