Question

A lnear harmonic oscillator of force constant $2\times {10}^{6}N/m$ and amplitude of $0.01m$ has mechanical energy of $160J$ its

• A. maximum potential energy is $100J$
• B. maximum kinetic energy is $100J$
• C. maximum potential energy is $160J$
• D. maximum potential energy is $0J$

Answer 1

Answer: (B), (C)

The correct options are
B maximum kinetic energy is $100J$
C maximum potential energy is $160J$

$\begin{array}{c}Harmonicoscillatorhassomeinitialelasticpotentialenergyandamplitudeofharmonic\\ variationofenergyis\\ \frac{1}{2}K{a}^2=\frac{1}{2}\times 2\times {10}^6{\left(0.01\right)}^2=100j\\ Thisisthemaximumkineticenergyoftheoscillator.Thus\\ K_{max}=100J\end{array}$

Hence, the option $B$ is the correct answer.