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Standard XII

Physics

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A load 'm' is...

Question

A load 'm' is attached to a spring of force constant 'k' and stretched it through 'x' and released. it makes oscillation in a vertical plane with a time period 'T'. It is further pulled down through another 'x' and released.Now the time period of vertical oscillation will be

\frac{T}{2}

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2 T

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T

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\frac{T}{4}

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Solution

The correct option is C $T$
Time period of vertical spring mass system is given by :
$T = 2 π \sqrt{\frac{m}{k}}$
so, on furthur extending the spring by 'x' results in greater amplitude, but time period remains same.
so, $T^{'} = T$

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A load 'm' is attached to a spring of force constant 'k' and stretched it through 'x' and released. it makes oscillation in a vertical plane with a time period 'T'. It is further pulled down through another 'x' and released.Now the time period of vertical oscillation will be

The correct option is C TTime period of vertical spring mass system is given by :T=2π√mkso, on furthur extending the spring by 'x' results in greater amplitude, but time period remains same.so, T′=T

The correct option is C $T$
Time period of vertical spring mass system is given by :
$T = 2 π \sqrt{\frac{m}{k}}$
so, on furthur extending the spring by 'x' results in greater amplitude, but time period remains same.
so, $T^{'} = T$