A load of $10 k g$ is suspended by a metal wire $3 m$ long and having a cross-sectional are $4 {m m}^{2}$ . Find (a) the stress (b) the strain and (c) the elongation. Young modulus of the metal is $2.0 \times 10^{11} N m^{- 2}$ .

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Solution

Force on the wire $= m g = 100 N$
Ans a -
Stress $(σ) = \frac{F}{A} = \frac{100}{4 \times 10^{- 6}} = 25 \times 10^{6} p a$
Ans b-
Strain $(ϵ) = \frac{σ}{Y} = \frac{25 \times 10^{6}}{2 \times 10^{11}} = 12.5 \times 10^{- 5}$
Ans c-
Elongation $(Δ l) = s t r a i n \times l e n g t h = 37.5 \times 10^{- 5} m$

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A load of 10 kg is suspended by a metal wire 3 m long and having a cross-sectional are 4 mm2. Find (a) the stress (b) the strain and (c) the elongation. Young modulus of the metal is 2.0×1011 Nm−2.

Force on the wire =mg=100NAns a - Stress (σ)=FA=1004×10−6=25×106paAns b-Strain (ϵ)=σY=25×1062×1011=12.5×10−5 Ans c-Elongation (Δl)=strain×length=37.5×10−5m

A load of $10 k g$ is suspended by a metal wire $3 m$ long and having a cross-sectional are $4 {m m}^{2}$ . Find (a) the stress (b) the strain and (c) the elongation. Young modulus of the metal is $2.0 \times 10^{11} N m^{- 2}$ .