A load of $100 k g$ is pulled up by $5 m .$ Calculate the work done.

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Solution

$M a s s = 100 k g$
$H e i g h t = 5 m$
$g = 9.8 m / s^{2}$

Work done = potential energy
$P E = m g h$

$= 100 \times 9.8 \times 5$
$= 4900 J$

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