A load of $220 k g$ is vertically pulled up by a crane through a vertical height of $16 m$ in $40 s$ . Calculate the force acting in the upward direction.
[Take g= $9.8 \frac{m}{s^{2}}$ ]

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Solution

Given:
Mass m = $220 k g$
g = $9.8 \frac{m}{s^{2}}$
Height = $16 m$
Time = $40 s$
The formula used: Force F = $m g$
To apply the formula:
$F = 220 \times 9.8 = 2156 N$
Answer:
Hence, the force acting in the upward direction is $2156 N$

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A load of 220kg is vertically pulled up by a crane through a vertical height of 16m in 40s. Calculate the force acting in the upward direction. [Take g=9.8ms2]

Given:Mass m = 220kg g = 9.8ms2 Height = 16m Time = 40sThe formula used: Force F = mgTo apply the formula:F=220×9.8=2156N Answer:Hence, the force acting in the upward direction is 2156N

A load of $220 k g$ is vertically pulled up by a crane through a vertical height of $16 m$ in $40 s$ . Calculate the force acting in the upward direction.
[Take g= $9.8 \frac{m}{s^{2}}$ ]

Given:
Mass m = $220 k g$
g = $9.8 \frac{m}{s^{2}}$
Height = $16 m$
Time = $40 s$
The formula used: Force F = $m g$
To apply the formula:
$F = 220 \times 9.8 = 2156 N$
Answer:
Hence, the force acting in the upward direction is $2156 N$