Question

A load of $220kg$ is vertically pulled up by a crane through a vertical height of $16m$ in $40s$. Calculate the force acting in the upward direction.

[Take g=$9.8\raisebox{1ex}{$m$}\!\left/ \!\raisebox{-1ex}{$s^2$}\right.$]

Answer 1

Given:

Mass m = $220kg$

g = $9.8\raisebox{1ex}{$m$}\!\left/ \!\raisebox{-1ex}{$s^2$}\right.$

Height = $16m$

Time = $40s$

The formula used: Force F = $mg$

To apply the formula:

$F=220\times 9.8=2156N$

Answer:

Hence, the force acting in the upward direction is $2156N$