A load of $220 k g$ is vertically pulled up by a crane through a vertical height of $16 m$ in $40 s$ . Calculate the total work done.
[Take g= $9.8 \frac{m}{s^{2}}$ ]

Open in App

Solution

Given:
Mass m = $220 k g$
g = $9.8 \frac{m}{s^{2}}$
Height = $16 m$
Time = $40 s$
To find force:
The formula used: Force F = $m g$
$F = 220 \times 9.8 = 2156 N$
To find work done:
The formula used: Work= $F \times s$
To apply the formula:
$W = m g \times h$
$W = 2156 \times 16 = 34496 J$
Hence, the total work done is $34496 J$

Suggest Corrections

Similar questions

Q. A load of 100 kg is pulled up by 5 m. Calculate the work done. (g = 9.8 m/s²)

Q. A boy weighing 50 kg climbs up a vertical height of 100 m. Calculate the amount of work done by him. How much potential energy does he gain? (g = 9.8 m/s²)

A load of $220 k g$ is vertically pulled up by a crane through a vertical height of $16 m$ in $40 s$ . Calculate the force acting in the upward direction.

[Take g= $9.8 \frac{m}{s^{2}}$ ]

A load of $220 k g$ is vertically pulled up by a crane through a vertical height of $16 m$ in $40 s$ .the Calculate horsepower of the engine pulling the rope.

[Take g= $9.8 \frac{m}{s^{2}}$ $1 H P = 750 W$ ]

A crane lifts a block of mass 400 kg through a vertical height of 40 m. If acceleration due to gravity is 9.8 m/s², calculate the work done by the crane.

Join BYJU'S Learning Program

A load of 220kg is vertically pulled up by a crane through a vertical height of 16m in 40s. Calculate the total work done. [Take g=9.8ms2]

Given:Mass m = 220kg g = 9.8ms2 Height = 16m Time = 40sTo find force:The formula used: Force F = mgF=220×9.8=2156N To find work done:The formula used: Work=F×sTo apply the formula:W=mg×hW=2156×16=34496JHence, the total work done is 34496J

A load of $220 k g$ is vertically pulled up by a crane through a vertical height of $16 m$ in $40 s$ . Calculate the total work done.
[Take g= $9.8 \frac{m}{s^{2}}$ ]