A load of $220 k g$ is vertically pulled up by a crane through a vertical height of $16 m$ in $40 s$ .the Calculate horsepower of the engine pulling the rope.
[Take g= $9.8 \frac{m}{s^{2}}$ $1 H P = 750 W$ ]

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Solution

Given:
Mass m = $220 k g$
g = $9.8 \frac{m}{s^{2}}$
Height = $16 m$
Time = $40 s$
To find force:
Formula used: Force F = $m g$
$F = 220 \times 9.8 = 2156 N$
To find work done:
Formula used: Work= $F \times s$
$W = m g \times h$
$W = 2156 \times 16 = 34496 J$
To find power:
Formula used: $p o w e r = \frac{w o r k}{t i m e}$
$P = \frac{3496}{40 = 87.4 W}$
To convert watt into horsepower:
$1 H P = 750 W$
$1 W = \frac{1}{750} H P$
$87.4 W = \frac{87.4}{750 = 1.15 H P}$
Hence, the horsepower of the engine pulling the rope is $1.15 H P$

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A load of 220kg is vertically pulled up by a crane through a vertical height of 16m in 40s.the Calculate horsepower of the engine pulling the rope. [Take g=9.8ms2 1HP=750W]

A load of $220 k g$ is vertically pulled up by a crane through a vertical height of $16 m$ in $40 s$ .the Calculate horsepower of the engine pulling the rope.
[Take g= $9.8 \frac{m}{s^{2}}$ $1 H P = 750 W$ ]