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Question

A load of 4.0 kg is suspended from a ceiling through a steel wire of length 20 m and radius 2.0 mm. It is found that the length of the wire increases by 0.031 mm as equilibrium is achieved. Find Young modulus of steel. Take g=3.1πms2.

A
1011N/m2
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B
2×1011N/m2
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C
3×1011N/m2
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D
4×1011N/m2
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Solution

The correct option is B 2×1011N/m2
The longitudinal stress =(4.0kg)(3.1πms2)π(2.0×103m)2
=3.1×106m)2.
The longitudinal strain =0.31×103m2.0m
=0.0155×103
Thus Y=3.1×106Nm20.0155×103=2.0×1011N m2.

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