A load of 4.0 kg is suspended from a ceiling through a steel wire of radius 2.0 mm. Find the tensile stress developed in the wire when equilibrium is achieved. Take g=3.1π ms−2.
3.1×106N/m2
Tension in the wire is
F = 4.0 ×3.1π N.
The area of cross section is
A=πr2=π×(2.0×10−3m)2
=4.0π×10−6 m2.
Thus, the tensile stress developed
=FA=4.0×3.1π4.0π×10−6N m−2
=3.1×106N m−2.