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Question

A load resistor of 2kΩ is connected in the collector branch of an amplifier circuit using a transistor in common-emitter mode. The current gain β = 50. The input resistance of the transistor is 0.50 kΩ. If the input current is changed by 50µA. (a) by what amount does the output voltage change, (b) by what amount does the input voltage change and (c) what is the power gain?

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Solution

Given:
Base current gain, β=50
Change in base current, δIb=50 μA
Load resistance,RL = 2 kΩ
Input resistance, Ri = 0.50 kΩ

(a) The change in output voltage is given by
V0=Ic×RLIc=β×IbV0=β×Ib×RLV0=50×50 μA×2 V0=5 V

(b) The change in input voltage is given by
δVi=δlb×RiδVi=50×10-6×5×102δVi=25×10-3δVi=25 mV

(c) Power gain is given by
β2×RLRi2500×20.52500×205=104

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