A local bus is carrying $40$ passengers, some with $50$ paisa tickets and the remaining with $R s 1.50$ tickets. If the total money collected from the passengers is $R s 32$ , then find the number of passengers with $50$ paisa tickets.

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Solution

Let x be no of
passengers with so paisa
tickets
$\frac{x}{2} + 1.5 (40 - x) = 32$
60-x=32
[x=28]

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A local bus is carrying 40 passengers, some with 50 paisa tickets and the remaining with Rs 1.50 tickets. If the total money collected from the passengers is Rs 32, then find the number of passengers with 50 paisa tickets.

Let x be no of passengers with so paisaticketsx2+1.5(40−x)=3260-x=32[x=28]

A local bus is carrying $40$ passengers, some with $50$ paisa tickets and the remaining with $R s 1.50$ tickets. If the total money collected from the passengers is $R s 32$ , then find the number of passengers with $50$ paisa tickets.

Let x be no of
passengers with so paisa
tickets
$\frac{x}{2} + 1.5 (40 - x) = 32$
60-x=32
[x=28]