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Question

# A locomotive of mass m starts moving with velocity v=α√s where α is constant s is distance traversed. The total work done by all the forces acting on the locomotive during first t sec.

A
12mα4t2
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B
14mα4t2
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C
18mα4t2
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D
116mα4t2
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Solution

## The correct option is C 18mα4t2A locomotive of mass =mVelocity v=α√sα= constants= distance transversedTotal work done by all the forces acting on the locomotive during first=tsecWork done= Force × displacement=mass×acceleration×Displacement=m×a22×(at2)2=m×a22×a2t24=18a4mt2

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