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Question

A locomotive of mass m starts moving with velocity v=αs where α is constant s is distance traversed. The total work done by all the forces acting on the locomotive during first t sec.

A
12mα4t2
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B
14mα4t2
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C
18mα4t2
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D
116mα4t2
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Solution

The correct option is C 18mα4t2
A locomotive of mass =m
Velocity v=αs
α= constant
s= distance transversed
Total work done by all the forces acting on the locomotive during first
=tsec
Work done= Force × displacement
=mass×acceleration×Displacement=m×a22×(at2)2=m×a22×a2t24=18a4mt2

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