A long block A is at rest on a smooth horizontal surface. A small block B (whose mass is half of A) is placed on A at one end and projected along A with a velocity v. The coefficient of friction is μ.Then,
A
the block will reach a final common velocity u/3.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
the work done against friction is 2/3 of initial KE of B.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
before the blocks reach a common velocity, the acceleration of A relative to B is 2/3μg.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
before the blocks reach a common velocity the acceleration of A relative to B is 3/2μg.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct options are A the block will reach a final common velocity u/3. B the work done against friction is 2/3 of initial KE of B. D before the blocks reach a common velocity the acceleration of A relative to B is 3/2μg. initial Momentum = Final Momentum (as no external force) mu=(m+2m)v ⇒v=u3 Intial KE Ki=12mu2 Final KE: Kf=12(m+2m)(u3)2=(16)mu2 Therefore work done against friction W=(12−16)mu2=13mu2=23Ki Force on B FB=−μmg ; Force on A FA=μmg Acceleration of B: aB=−μg; Acceleration of A: aA=μg2; Relative acceleration between A and B: aAB=μg+μg2=32μg