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Question

A long block A is at rest on a smooth horizontal surface. A small block B (whose mass is half of A) is placed on A at one end and projected along A with a velocity v. The coefficient of friction is μ.Then,

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A
the block will reach a final common velocity u/3.
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B
the work done against friction is 2/3 of initial KE of B.
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C
before the blocks reach a common velocity, the acceleration of A relative to B is 2/3μg.
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D
before the blocks reach a common velocity the acceleration of A relative to B is 3/2μg.
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Solution

The correct options are
A the block will reach a final common velocity u/3.
B the work done against friction is 2/3 of initial KE of B.
D before the blocks reach a common velocity the acceleration of A relative to B is 3/2μg.
initial Momentum = Final Momentum (as no external force)
mu=(m+2m)v
v=u3
Intial KE Ki=12mu2
Final KE: Kf=12(m+2m)(u3)2=(16)mu2
Therefore work done against friction W=(1216)mu2=13mu2=23Ki
Force on B FB=μmg ; Force on A FA=μmg
Acceleration of B: aB=μg;
Acceleration of A: aA=μg2;
Relative acceleration between A and B: aAB=μg+μg2=32μg

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