wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A long glass tube is held vertically in the water. A tuning fork is struck and held over the tube. Strong resonances are observed at two successive lengths 0.50m and 0.84m above the surface of the water. If the velocity of sound is 340m/s, then the frequency of the tuning fork is (neglect end corrections)

A
128Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
256Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
384Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
500Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 500Hz
For given data:
The velocity of the sound =340m/s

Resonance observed at two successive lengths l1=0.50m and l2=0.84m.
λ2=(l2l1)=(0.840.5)m=0.34m

λ=0.34×2m=0.68m

To find; Frequency of tunning fork

We know the formula
Frequency, f=vλ

=3400.68

f=500Hz
Frequency of tuning fork is 500Hz

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Standing Longitudinal Waves
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon