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Question

A long glass tube is held vertically in the water. A tuning fork is struck and held over the tube. Strong resonances are observed at two successive lengths 0.50m and 0.84m above the surface of the water. If the velocity of sound is 340m/s, then the frequency of the tuning fork is (neglect end corrections)

A
128Hz
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B
256Hz
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C
384Hz
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D
500Hz
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Solution

The correct option is D 500Hz
For given data:
The velocity of the sound =340m/s

Resonance observed at two successive lengths l1=0.50m and l2=0.84m.
λ2=(l2l1)=(0.840.5)m=0.34m

λ=0.34×2m=0.68m

To find; Frequency of tunning fork

We know the formula
Frequency, f=vλ

=3400.68

f=500Hz
Frequency of tuning fork is 500Hz

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