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Question

A long narrow horizontal slit is paced 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and that after reflection is seen on a screen 1⋅0 m away from the slit. Find the fringe-width if the light used has a wavelength of 700 nm.


Solution

Given:
Separation between two slits, d'=2d=2 mm=2×10-3 m (as d = 1 mm)
Wavelength of the light used, λ=700 nm=700×10-3 m     
Distance between the screen and slit (D) = 1.0 m
It is a case of Lloyd's mirror experiment.
Fringe width, β=λDd'                  =700×10-9×12×10-3                  =0.35×10-3 m=0.35 mm

Hence, the width of the fringe is 0.35 mm.

Physics
HC Verma - I
Standard XI

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