The correct option is
B 32 ΩIn the given circuit the resistance
25 Ω is in parallel to
100 Ω resistance, thus equivalent resistance of these two resistances is given as,
R1=100×25100+25=20 Ω
Now the circuit is reduced as follows,
From above figure we can see that resistance
20 Ω and
100 Ω are in series and in parallel with
120 Ω.
So the equivalent resistance is given as,
R2=120×120120+120=60 Ω
Now the circuit is further reduced as follows,
100 Ω and
60 Ω resistance are in series which is in parallel with
40 Ω resistance. So the equivalent resistance between terminals
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A and
B is given as,
R=160×40160+40=32 Ω
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Hence, option (b) is the correct answer.