A long solenoid is formed by the winding $20 t u r n s / c m$ . What will be the current necessary to produce a magnetic field of $20 m i l l i t e s l a$ inside the solenoid?
( $\frac{μ_{0}}{4 π} = 10^{- 7} t e s l a - m e t e r / a m p e r e$ )

8.0 A

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4.0 A

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2.0 A

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1.0 A

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Solution

The correct option is C $8.0 A$
The magnetic field due to a long solenoid is:
$B = μ_{0} n i$

$\Rightarrow i = \frac{B}{μ_{0} n}$

$= \frac{20 \times 10^{- 3}}{4 π \times 10^{- 7} \times 20 \times 100}$

$= 7.9 a m p = 8 a m p$

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