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Standard X

Physics

Bar Magnet

A long soleno...

Question

A long solenoid with 10 turn /cm and a radius of 7.0 cm carries a current of 20.0 mA. A current 6.0 A exists in a straight conductor located along the central axis of the solenoid. At what radial distance from the axis the direction of the magnetic field be at $45^{\circ}$ to the axial direction

4.8 cm

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8.1 cm

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9.9 cm

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10.6 cm

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Solution

The correct option is A 4.8 cm
$\begin{matrix} μ_{o} n i = \frac{μ_{o} i}{2 π x} \Rightarrow 1000 \times 20 \times 10^{- 3} = \frac{6}{2 x π} x = \frac{6}{10 \times π} \times 100 c m \approx 4.8 m H e n c e, t h e o p t i o n A i s t h e c o r r e c t a n s w e r . \end{matrix}$

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A long solenoid with 10 turn /cm and a radius of 7.0 cm carries a current of 20.0 mA. A current 6.0 A exists in a straight conductor located along the central axis of the solenoid. At what radial distance from the axis the direction of the magnetic field be at 45∘ to the axial direction

The correct option is A 4.8 cmμoni=μoi2πx⇒1000×20×10−3=62xπx=610×π×100cm≈4.8mHence,theoptionAisthecorrectanswer.

A long solenoid with 10 turn /cm and a radius of 7.0 cm carries a current of 20.0 mA. A current 6.0 A exists in a straight conductor located along the central axis of the solenoid. At what radial distance from the axis the direction of the magnetic field be at $45^{\circ}$ to the axial direction

The correct option is A 4.8 cm
$\begin{matrix} μ_{o} n i = \frac{μ_{o} i}{2 π x} \Rightarrow 1000 \times 20 \times 10^{- 3} = \frac{6}{2 x π} x = \frac{6}{10 \times π} \times 100 c m \approx 4.8 m H e n c e, t h e o p t i o n A i s t h e c o r r e c t a n s w e r . \end{matrix}$