Question

A long straight wire carries a current $I_0=100$ amp.A particle having a positive charge q=100C and mass m=10g is kept at a distance $x_0=10m$ from the wire is projected away from it with a speed
$v_0=10m/sec$. The maximum separation between particle and wire is found to be y( 10) m. Find y. $[Take{e}^{100}=3]$. ___

Answer 1

$<B>\frac{{\int }_x^x\frac{{\mu }_0{I}_{0}dr}{2\pi r}}{{\int }_x^{x}dr}\Rightarrow \frac{{\mu }_0{I}_{0}In\frac{x_0}{x}}{(x_0-x)}\Rightarrow x_0-x=\frac{m{\mu }_0(x_0-x)}{\frac{q{\mu }_{0}I}{2\lambda }In\left(\frac{{\mu }_0}{\mu }\right)}$
$x=x_{0}e\frac{2\pi m{v}_0}{{\mu }_{0}q{I}_0}=30=3\left(10\right)$
$y=3$