Question

A long, straight wire carries a current I passing through the center of square loop. If side of square loop is s then calculate the induced current in the square loop.

• A. $\frac{2{\mu }_{0}Is}{\pi (1+\sqrt{2})}$
• B. $\frac{{\mu }_{0}Is}{\pi \sqrt{2}}$
• C. $\frac{{\mu }_{0}Is}{\pi }$
• D. $\frac{{\mu }_{0}Is\sqrt{2}}{\pi }$
• E. 0

Answer 1

Answer: (E)

0

According to Faraday , current is induced in a loop only when the magnetic flux linked with loop changes with time ,in the given figure we can see that there is no flux linked with loop because the direction of magnetic field is perpendicular the area vector of loop besides this loop is static and mag. field is also constant with time therefore by

$\varphi =BA\cos 90=0$

so $e=-d\varphi /dt=0$

so no induced emf and thus no induced current.