A long straight wire carries a current of 35 A. What is the magnitude of the field B at a point 20 cm from the wire?
Given: The current in the wire is 35 A , the distance of a point from the wire is 20 cm .
The magnitude of the magnetic field at this point is given as:
| B → | = μ 0 4 π 2 I r
Where, the current in the wire is I , the distance of a point from the wire is r , and the permeability of free space is μ 0 .
By substituting the given values in the above expression, we get
| B → | = 4 π × 10 − 7 4 π 2 × 35 0.2 = 3.5 × 10 − 5 T
Thus, the magnitude of the magnetic field at a point 20 cm from the wire is 3.5 × 10 − 5 T .
Given: The current in the wire is
The magnitude of the magnetic field at this point is given as:
Where, the current in the wire is
By substituting the given values in the above expression, we get
Thus, the magnitude of the magnetic field at a point
